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# More help with probability?

Topic: Case summation
June 16, 2019 / By Shelia
Question: 2 cubes are tossed and the top faces are observed what is the possibility that the sum is even or the sum is >4 also probability that the sum is even or sum is >5 Ha-Ha im not good with math I can write nice essays + summarize things well using WORDS I can explain things concerning history i can summarize biological processes and explain structure/function I can write an essay using substantial evidence and figurative language I cannot do logarithms x_x

## Best Answers: More help with probability?

Pauline | 6 days ago
I would assume that you are talking about a cube being a dice. In that case, then the possible summation of the two cubes are: 1 + 1.....2 + 1......3 + 1.....4 + 1.....5 + 1.....6 + 1 1 + 2.....2 + 2......3 + 2.....4 + 2.....5 + 2.....6 + 2 1 + 3.....2 + 3......3 + 3.....4 + 3.....5 + 3.....6 + 3 1 + 4.....2 + 4......3 + 4.....4 + 4.....5 + 4.....6 + 4 1 + 5.....2 + 5......3 + 5.....4 + 5.....5 + 5.....6 + 5 1 + 6.....2 + 6......3 + 6.....4 + 6.....5 + 6.....6 + 6 you have 36 possibilities in total, so the probability that the sum is greater than 4 is: 30/36 = 5/6 The probability the sum is greater than 5 is: 26/30 = 13/15
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We found more questions related to the topic: Case summation

Originally Answered: More help with probability?
I would assume that you are talking about a cube being a dice. In that case, then the possible summation of the two cubes are: 1 + 1.....2 + 1......3 + 1.....4 + 1.....5 + 1.....6 + 1 1 + 2.....2 + 2......3 + 2.....4 + 2.....5 + 2.....6 + 2 1 + 3.....2 + 3......3 + 3.....4 + 3.....5 + 3.....6 + 3 1 + 4.....2 + 4......3 + 4.....4 + 4.....5 + 4.....6 + 4 1 + 5.....2 + 5......3 + 5.....4 + 5.....5 + 5.....6 + 5 1 + 6.....2 + 6......3 + 6.....4 + 6.....5 + 6.....6 + 6 you have 36 possibilities in total, so the probability that the sum is greater than 4 is: 30/36 = 5/6 The probability the sum is greater than 5 is: 26/30 = 13/15
Originally Answered: More help with probability?
Cases of sum < or = 4: 1-1, 1-2, 1-3, 2-1, 2-2, 3-1 P(sum > 4) = 1 - 6/6^2 = 5/6 ---------- Ideas: Use supplement property.

Marigold
Cases of sum < or = 4: 1-1, 1-2, 1-3, 2-1, 2-2, 3-1 P(sum > 4) = 1 - 6/6^2 = 5/6 ---------- Ideas: Use supplement property.
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Kourtney
Well, List the sample space. What is the total number of possible answers. Then, what number of them are less than 4? Your answer is TOTAL AMOUNT over LESS THAN 4
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Originally Answered: Probability & Statistics Problems:Guys I'd really appreciate your help on this.I've tried all i could,nothing?
Not enough info for #6. #7 You want to find c so that P(X

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