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Can you solve this cryptogram?

Can you solve this cryptogram? Topic: How to write a letter to the editor of newspaper
June 16, 2019 / By Cortney
Question: Each letter in the below has been replaced through out the passage by another letter; it's a simple substitution cipher or cryptogram like one finds in newspapers. This one actually looks a bit longer, but that should actually help you break it. The assignment is, naturally, to solve the message. Perhaps you might start with a letter frequency count or histogram if it doesn't fall to intelligent guesswork? Be sure to show your work, and/or include your work sheets with the finished solution. "N SBAH KUBAHYHM KSH YHOXKS BOM WUHBMKS JC KSNP RJFOKUL BOM KBYDHM VNKS KSH WHPK EHJEYH BOM N RBO BPPFUH LJF KSBK MBKB EUJRHPPNOX NP B CBM KSBK VNYY OJK YBPK JFK KSH LHBU." RSNHC HMNKJU JC EUHOKNRH SBYY WJJDP, 1957.
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Best Answers: Can you solve this cryptogram?

Asaf Asaf | 6 days ago
I have traveled the length and breadth of this country and talked with the best people and I can assure you the data processing is a fad that will not last out the year chief editor of prentice hall books 1957 for the person who wanted to know how to do it-you should write it down-look for single letters they are either a or I..look for double letters and words that begin and end in the same letter-usually it is "that" also look for a four letter word with the same 2nd and 4th letter as it is usually an e
👍 100 | 👎 6
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Asaf Originally Answered: Can you solve this cryptogram?
I have traveled the length and breadth of this country and talked with the best people and I can assure you the data processing is a fad that will not last out the year chief editor of prentice hall books 1957 for the person who wanted to know how to do it-you should write it down-look for single letters they are either a or I..look for double letters and words that begin and end in the same letter-usually it is "that" also look for a four letter word with the same 2nd and 4th letter as it is usually an e
Asaf Originally Answered: Can you solve this cryptogram?
"I have traveled the length and breadth of this country and talked with the best people and I can assure you that data processing is a fad that will not last out the year." chief editor of prentice hall books, 1957.

Valarie Valarie
"I have traveled the length and breadth of this country and talked with the best people and I can assure you that data processing is a fad that will not last out the year." chief editor of prentice hall books, 1957.
👍 30 | 👎 0

Schuyler Schuyler
"I HAVE TRAVELED THE LENGTH AND BREADTH OF THIS COUNTRY AND TALKED WITH THE BEST PEOPLE AND I CAN ASSURE YOU THAT DATA PROCESSING IS A FAD THAT WILL NOT LAST OUT THE YEAR." CHIEF EDITOR OF PRENTICE HALL BOOKS, 1957.
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Schuyler Originally Answered: Solve. -5≤2-h or 6h+5≥71?
There are three theorems that make solving this problem or almost any other inequality problem relatively easy --------------------------- Theorem 1) You may add or subtract any number from all parts of the inequality without changing the directions of the inequality signs. Theorem 2) You may multiply or divide the parts of an inequality by a ***positive*** number without changing the directions of the inequality signs. Theorem 3) If you multiply or divide the parts of an inequality by a ***negative*** number then you ***must change the directions of all of the inequality signs.*** _____________ After each step I will put the number of the theorem (rule) that I have used in parentheses, like (2) for "I used Theorem 2" _____________ 1) -5 <= 2 - h Add h to both sides of this equation (1), getting: h - 5 <= 2.....Add 5 to both sides of this equation (1) h <= 7......That's the first part 2) 6h + 5 >= 71......Subtract 5 from both sides of this equation (1) 6h >= 66.....Divide both sides by 11 which is positive (2), getting: h > 11 The answer is h <= 7 or h >= 11.....<<<<<.....First Answer ______________________________ |2d + 8| < 2 There are two cases: Case 1: Assume that 2d + 8 >= 0 Case 2: Assume that 2d + 8 < 0 ___________ Case 1: Assume that 2d + 8 > 0 Then |2d + 8| = 2d + 8 So the problem becomes: 2d + 8 < 2.....Subtract 8 from both sides (1) 2d < -6.....Divide by 2 (2) d < - 3 Case 2: 2d + 8 < 0 Then multiplying both sides of this equation by (-1) and using Theorem 3, -2 - 8d > 0......Since it is positive |2d + 8| = -2 - 8d So to solve |2d + 8| < 2 we have to solve -2 - 8d < 2 since they are equal (|2d + 8| and -2d - 8 (in Case (2)) -2d - 8 < 2.....Add 8 to both sides (1) -2d < 10.....Divide both sides by 2 (2) -d < 5........Multiply both sides by (-1) to get rid of the minus signs (3) d > -5 ------------ So combining Case 1) and Case 2) -5 < d < -3.....<<<<<.....Second Answer Guess what - I used to teach math. What I am writing here is not preaching, just telling you how to take advantage of the three theorems and imitating what I did with them. By giving you the three rules and showing how I apply them, I hope that I have succeeding in teaching you how to do these problems with inequalities. When you do the rest of your homework use the three theorems and apply them as I did here and you should not have any problems. .

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