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Chemistry Stoichiometry Word Problem involving mole ratios.?

Chemistry Stoichiometry Word Problem involving mole ratios.? Topic: How to write a decomposition reaction
June 16, 2019 / By Krista
Question: Hi everyone! Okay, so here's the problem: The decomposition of potassium chlorate, KCLO3, is used as a source of oxygen in the laboratory. How many moles of potassium chlorate are needed to produce 15 mol of oxygen gas? Alright, so first off, I wrote the mole ratios: KClO3 -> K + ClO + O2 I think that ratio was wrong, but the textbook did not deal with any reactions like this, since it doesn't really give you the equation? I just thought O2 is oxygen gas... so the ratio is 1 mol KClO3 / 1 mol O2 Then, I put it in the equation, with variable x as the amount of moles of potassium chlorate needed to produce 15 mol of oxygen gas. x mol KClO3 x 1 mol O2/ 1 mol KClO3 = 15 mol O2 Then, I got 15 mol O2, and I'm pretty sure that is wrong, since the answer key says the correct answer is 10. Anyways, I think there's something I did wrong in writing the equation and finding the ratios (wrong ratio, I suppose, but I don't know why or what I did) Help would be very much appreciated!
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Best Answers: Chemistry Stoichiometry Word Problem involving mole ratios.?

Jayna Jayna | 1 day ago
Actually I don't like to write an extra answer to the questions already answered, if I don't see any point to be corrected. The decomposition reaction is wrong. Potassium is one of the most active elements and it cannot be obtained by heating one of its salt. Even in pure form, it is stored in gasoline because it is easily oxidized by the oxygen in air. Any way, the correct decomposition reaction; 2KClO3 (s) ----------> 2KCl (s) + 3O2 (g) For 3 moles of O2, we need 2 moles of KClO3 For 15 moles of O2, we need; 2 mol KClO3 x (15 mol O2 / 3 mol O2) = 10 mol KClO3
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Jayna Originally Answered: Chemistry Stoichiometry Word Problem involving mole ratios.?
Actually I don't like to write an extra answer to the questions already answered, if I don't see any point to be corrected. The decomposition reaction is wrong. Potassium is one of the most active elements and it cannot be obtained by heating one of its salt. Even in pure form, it is stored in gasoline because it is easily oxidized by the oxygen in air. Any way, the correct decomposition reaction; 2KClO3 (s) ----------> 2KCl (s) + 3O2 (g) For 3 moles of O2, we need 2 moles of KClO3 For 15 moles of O2, we need; 2 mol KClO3 x (15 mol O2 / 3 mol O2) = 10 mol KClO3
Jayna Originally Answered: Chemistry Stoichiometry Word Problem involving mole ratios.?
first you need to balance the reaction equation that is given; 2KClO3 -> 2K + 2ClO + 2O2 (decomposition reaction) thus, according to the balanced reaction equation, the mole ratio between KClO3 and O2 is 2:2 (or 1:1 if you simplify.) Thus, you are right - 15 mol of oxygen gas will be produced from 15 moles of KClO3. Hope this helps:-D

Evie Evie
first you need to balance the reaction equation that is given; 2KClO3 -> 2K + 2ClO + 2O2 (decomposition reaction) thus, according to the balanced reaction equation, the mole ratio between KClO3 and O2 is 2:2 (or 1:1 if you simplify.) Thus, you are right - 15 mol of oxygen gas will be produced from 15 moles of KClO3. Hope this helps:-D
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Evie Originally Answered: Should I get this mole removed?
my frnd got her removed, although it was not as huge as you describe, but she didn't had any scars? so not sure, but if it is not visible,let it be ther

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